Question

am nevoie va rog frumos !!!!!doar b,c,d​

Answer 1

Răspuns:

b) (a - b) × c = a × c - b × c = 11/15 - 13/24

Numitor comun 2^3 × 3 × 5 = 120

(88 - 65)/120 = 23/120

c) a × b + 2 × a × c - a × d = a × (b + 2c - d) =

4/9 × (b + c + c - d) =

4/9 × (15/8 + 9/20) =

Numitor comun în paranteză 2^3 × 5 = 40

(75 + 18)/40 = 93/40

4/9 × 93/40 = 31/30

d) a × (b + c + d) = a × b + a × c + a × d =

5/12 + 9/20 + 7/15 =

Numitor comun

12 = 2^2 × 3

20 = 2^2 × 5

15 = 3 × 5

__________

cmmmc = 2^2 × 3 × 5 = 60

(25 + 27 + 28)/60 = 80/60 = 8/6 = 4/3

a × (b + c - d) = a × b + a × c - a × d =

5/12 + 9/20 - 7/15 =

(25 + 27 - 28)/60 = 24/60 = 2/5