Question

Am pus o poza cu exeritiul :)

Answer 1

Răspuns:

a) 2³ = 2•2•2 = 8

b) 3² = 3•3 = 9

c) 4^-1 = 1/4

d) 5^-2 = 1/5² = 1/25

e) (1/2)³ = 1³/2³ = 1/8

f) (1/3)^-2 = 3² = 9

g) √5² = 5

h) √2³ = 2√2

i) (-√5)⁴ = √5⁴ = 5² = 25

j) √3^5 = 3²•√3 =9√3

k) 1^219 = 1

l) 0^202 = 0

m) (-1)^119 = -1^119 = -1

n) (-1)^-299 = -1

EVERGREEN

Answer 2

$\it c)\ 4^{-1}=\dfrac{1}{4};\ \ d)\ 5^{-2}=\dfrac{1}{5^2}=\dfrac{1}{25};\ \ e)\ \Big(\dfrac{1}{2}\Big)^3=\dfrac{1^3}{2^3}=\dfrac{1}{8}\\ \\ \\ f)\ \Big(\dfrac{1}{3}\Big)^{-2}=\Big[\Big(\dfrac{1}{3}\Big)^{-1}\Big]^2=3^2=9\\ \\ \\ g)\ (\sqrt5)^2=5;\ h)\ (\sqrt2)^3=(\sqrt2)^2\cdot\sqrt2=2\sqrt2\\ \\ i)\ (-\sqrt5)^4=(\sqrt5)^4=(\sqrt5^2)^2=5^2=25\\ \\ j)\ (\sqrt3)^5=(\sqrt3)^4\cdot\sqrt3=(\sqrt5^2)^2\sqrt5=5^2\sqrt5=25\sqrt5\\ \\ k)\ 1^{219}=1;\ \ell)\ 0^202=0;\ m)\ (-1)^119=-1;\ n)\ (-1)^{-299}=-1$