Question

am si eu nevoie de 1 si 2 va rog!!​

Answer 1

Răspuns:

Explicație pas cu pas:

a) b₁ = 6 ; q = 2 ; b₂ = b₁q = 6·2 = 12 ; b₃ = b₂·q = 12·2 = 24

b₄ = 24·2 = 48 ; b₅ = 48·2 = 96

b) b₂ = -10 ; q = 1/2

b₁ = b₂/q = -10/(1/2) = -10·2 = -20

b₃ = b₂q = -10·1/2 = -5

b₄ = b₃q = -5·1/2 = -5/2

b₅ = b₄q = -5/2 ·1/2 = -5/4

c) b₁ = -24 ; q = -0,5 ; b₂ = b₁q = (-24)·(-0,5) = 12

b₃ = b₂q = 12·(-1/2) = -6

b₄ = b₃q = -6·(-1/2) = 3

b₅ = b₄q = 3·(-1/2) = -3/2

d) b₂ = 0,5 = 1/2 ; q = √3

b₁ = b₂/q = 1/(2√3) = √3/6

b₃ = b₂q = 1/2 ·√3 = √3/2

b₄ = 3/2 ; b₅ = 3√3/2

e) b₁ = 3 ; q = -2 ; b₂ = -6 ; b₃ = 12 ; b₄ = -24 ; b₅ = 48

f) b₈ = 384 = 3·2⁷; q = 2 ; b₁ = b₈/q⁷ = 3·2⁷/2⁷ => b₁ = 3

b₂ = 3·2 = 6 ; b₃ = 12 ; b₄ = 24 ; b₅ = 48

2) a) y₁ ; y₂ ; 24 ; 36 ; 54 ......

q = b₅/b₄ = 54/36 = 3/2

q = b₄/b₃ = 36/24 = 3/2

b₂ = b₃/q = 24 : 3/2 = 24·2/3 = 16

b₁ = b₂/q = 16 : 3/2 = 16·2/3 = 32/3

b) y₁ ; y₂ ; 225 ; -135 ; 81 .............

q = b₅/b₄ = 81/(-)135 = -3/5

y₂ = 225/(-3/5) = (225·5)/(-3) = -375

y₁ = -375 / (-3/5) = (375·5)/3 = 625