Question

Am și eu nevoie de ajutor aici va rog mult e urgent dau coroana ​

Answer 1

$x=\left(\frac{2}{\sqrt{12}}+\frac{9}{\sqrt{27}}+\frac{6}{\sqrt{108}}\right)\left(\frac{1}{\sqrt{3}}\right)^{-1}$

$x=\left(\frac{1}{\sqrt{3}}\right)^{-1}\left(\frac{1}{\sqrt{3}}+\frac{9}{\sqrt{27}}+\frac{6}{\sqrt{108}}\right)$

$x=\left(\frac{1}{\sqrt{3}}\right)^{-1}\left(\frac{1}{\sqrt{3}}+\frac{3}{\sqrt{3}}+\frac{6}{\sqrt{108}}\right)$

$=\left(\frac{1}{\sqrt{3}}\right)^{-1}\left(\frac{1}{\sqrt{3}}+\frac{1}{\sqrt{3}}+\frac{3}{\sqrt{3}}\right)$

$x=\sqrt{3}\left(\frac{1}{\sqrt{3}}+\frac{1}{\sqrt{3}}+\frac{3}{\sqrt{3}}\right)$

$x=\sqrt{3}\left(\frac{5\sqrt{3}}{3}\right)$

$x=\frac{5\sqrt{3}}{3}\sqrt{3}$

$x=\frac{5\sqrt{3}\sqrt{3}}{3}$

$x=\frac{15}{3}$

$x =5$

$y=\left(5^6\right)^3\cdot 25^3:125^8$

$y=\frac{\left(5^6\right)^3\cdot \:25^3}{125^8}$

$y =\frac{5^{18}\cdot \:5^6}{5^{24}}$

$y =\frac{5^{24}}{5^{24}}$

$y=1$

Sper ca te-am ajutat!