Question

Am si eu nevoie de ajutor la ex A1 B SUBPUNCTUL d va rog mult!

Answer 1

Răspuns:

1

Explicație pas cu pas:

$(\dfrac{3^\sqrt{5} }{3^\sqrt{2}})^{\sqrt{5}+\sqrt{2}} *(\dfrac{3^\sqrt{7} }{3^\sqrt{10}})^{\sqrt{7}+\sqrt{10}} =(3^{\sqrt{5}-\sqrt{2}})^{\sqrt{5}+\sqrt{2}}*(3^{\sqrt{7}-\sqrt{10}})^{\sqrt{7}+\sqrt{10}}=3^{(\sqrt{5}-\sqrt{2})(\sqrt{5}+\sqrt{2})}*$$*3^{(\sqrt{7}-\sqrt{10})(\sqrt{7}+\sqrt{10})}=3^{(\sqrt{5})^2-(\sqrt{2})^2}*3^{(\sqrt{7})^2-(\sqrt{10})^2}=3^{5-2}*3^{7-10}=3^3*3^{-3}=3^{3+(-3)}=3^0=1.$

Answer 2

$\it\ = \dfrac{3^{\sqrt5(\sqrt5+\sqrt2)+\sqrt7(\sqrt7+\sqrt{10})}}{3^{\sqrt2(\sqrt5+\sqrt2)+\sqrt{10}(\sqrt7+\sqrt{10})}}=3^{(\sqrt5+\sqrt2)(\sqrt5-\sqrt2)+(\sqrt7+\sqrt{10})(\sqrt7-\sqrt{10})}=\\ \\ \\ =3^{3+(-3)}=3^0=1$