Question

Am si eu nevoie de ajutor la exercitiul 4 a!!

Answer 1

$\displaystyle \frac{24}{ \sqrt{3} } + \frac{30}{5 \sqrt{3} }- \frac{42}{7 \sqrt{3} } + \frac{36}{ \sqrt{3} } = \frac{24 \sqrt{3} }{3} + \frac{30 \sqrt{3} }{5 \cdot 3} - \frac{42 \sqrt{3} }{7 \cdot 3} + \frac{36 \sqrt{3} }{3} = \\ \\ = \frac{24 \sqrt{3} }{3} + \frac{30 \sqrt{3} }{15} - \frac{42 \sqrt{3} }{21} + \frac{36 \sqrt{3} }{3} =8 \sqrt{3} +2 \sqrt{3} -2 \sqrt{3} +12 \sqrt{3} = \\ \\ =10 \sqrt{3} -2 \sqrt{3} +12 \sqrt{3} =8 \sqrt{3} +12 \sqrt{3} =20 \sqrt{3}$