Question

Am și eu nevoie de ajutor urgent va rog!

Answer 1

Răspuns:

Reactia de combinare reprezinta procesul chimic de formare a unui singur produs de reactie o substanta compusa.

1. 2H2 + O2 → 2H2O - apă

2. H2 +Cl2 → 2HCl - acid clorhidric

3. H2 +3N2 → 2NH3 - amoniac

4. NH3 + HCl → NH4Cl - clorura de amoniu

5. 2Mg + O2 → 2MgO - oxid de magneziu

6. MgO +  H2O → Mg(OH)2 - hidroxid de magneziu

7. 2Fe + 3Cl2 → 2FeCl3 clorura de fier III

8. Mg + Cl2 → MgCl2 cloruar de magneziu

2.

MH2=2x1=2g/mol

MCl2=2x35,5=71g/mol

m=nxM=7x71=497gCl2

2g........71g

H2  +  Cl2 → 2HCl

xg.........497g

x=2x497/71=calculeaza

3.

MH2=2x1=2g/mol

MNH3=14+3x1=17g/mol

3x2g.............2x17g

3H2 + N2 → 2NH3

24g....................xg

x=24x2x17/3x2=calculeaza

4.

MNH3=14+3x1=17g/mol

17g NH3..............3gH

100gNH3..............x%H

x=100x3/17=calculeaza

MH2O=2x1+16=18g/mol

18g H2O.............2gH

100gH2O............y%H

y=100x2/18=calculeaza

MCH4=12+4x1=16g/mol

16gCH4.............4gH

100gCH4...........z%H

z=100x4/16=calculeaza

5.

MCl2=2x35,5=71g/mol

MAlCl3=27+3x35,5= 133,5g/mol

m=nxM=9x71=639gCl

         3x71g....2x133,5g

2Al + 3Cl2 → 2AlCl3

          639g........xg

x=639x2x1335,5/3x71=calculeaza

calculam in moli

       3moli.....2moli

2Al + 3Cl2 → 2AlCl3

          9moli.....ymoli

y=9x2/3=calculeaza

Explicație:

a=O oxigen

b= Cl -clor

d= N azot

e= NH4Cl - clorura de amoniu

f= MgO - oxid de magneziu

g= Mg(OH)2 - hidroxid de magneziu

h=FeCl3 clorura de fier III

i=  MgCl2 cloruar de magneziu