Question

Am si eu nevoie de cel insemnat!Va rog,mult!

Answer 1

[(x²+4x+3)/(x²+2x-3) - 2/(x+1) - 7/(x-1)] : 1/(x²-1)=

x²+4x+3 =x²+3x+x+3 =x(x+3)+(x+3)=(x+3)(x+1)
x²+2x-3 =x²+3x-x-3 =x(x+3)-(x+3)=(x+3)(x-1)
x²-1=(x-1)(x+1)

=[(x+3)(x+1)/(x+3)(x-1) - 2/(x+1) - 7/(x²-1)] : 1/(x-1)(x+1)=
=[(x+1)/(x-1) - 2/(x+1) - 7/(x-1)] × (x-1)(x+1)=
=[(x+1)²-2(x-1) - 7)/(x-1)(x+1)] × (x-1)(x+1)=
=(x²+2x+1-2x+2 - 7)/(x-1)(x+1) × (x-1)(x+1)=
=x²-4