Question

am si eu nevoie de rezolvarea la ex 33, pls dau coroana​

Answer 1

Răspuns:

$(2x + 3)^{2} = 4 {x}^{2} + 12x + 9$

$(x - 3)(x + 2) = {x}^{2} - x - 6$

$(x + 2)^{2} = {x}^{2} + 4x + 4$

$x(x + 7) = {x}^{2} + 7x$

$e(x) = 4 {x}^{2} + 12 x + 9 - {x}^{2} + x + 6 - {x}^{2} - 4x - 4 - {x}^{2} - 7x - 10$

$e(x) = {x}^{2} + 2x + 1 \\ e(x) = {(x + 1)}^{2}$