Question

Am si eu nevoie de rezolvarile la ex 3,4 va rog!!,
Multumesc!❤️

Answer 1

Răspuns:

?????????!!!!!!!♡♡♡♡♡♡♡

Answer 2

Răspuns:

Explicație pas cu pas:

$[\sqrt{10}-(-2\sqrt{10})^{3} ]:|-9\sqrt{2}|=[\sqrt{10} +2^{3}*(\sqrt{10} )^{3}]:9\sqrt{2}=[\sqrt{10}+8*( \sqrt{10})^{2}*\sqrt{10}]:9\sqrt{2}=[\sqrt{10}+80\sqrt{10}]: 9\sqrt{2}=[\frac{81\sqrt{10}}{9\sqrt{2}}=9*\sqrt{\frac{10}{2} }=9\sqrt{5}$

$a=1,(6)*(\frac{11}{2\sqrt{75}}-\frac{8}{\sqrt{48} })=\frac{16-1}{9}*( \frac{11}{2\sqrt{25*3}}-\frac{8}{\sqrt{16*3} })=\frac{15}{9}*(\frac{11}{10\sqrt{3} }-\frac{2}{\sqrt{3} })=\frac{15}{9}*(\frac{11\sqrt{3}}{10*3 }-\frac{2\sqrt{3}}{3})=\frac{15}{9}*(\frac{11\sqrt{3}}{10*3 }-\frac{10*2\sqrt{3}}{30})=\frac{15}{9}*\frac{-9\sqrt{3} }{30} =-\frac{\sqrt{3} }{2}. \\Deci~|a|=|-\frac{\sqrt{3} }{2}|=\frac{\sqrt{3} }{2}$