Question

amestecul format dinNaCl shi KCl cu masa de 20,75g afost tratat cu solutie de AgNO3shi in cosecinte sa format un precipitat AgClcu masa de 43,05g .calculati masa la toate]

Answer 1

nr moli AgCl = 43.05 /143.5=0.3 moli

1.................................1
NaCl + AgNO3 = AgCl + NaNO3
x.................................x

1................................1
KCl + AgNO3 = AgCl + Na NO3
y..............................y

x+y = 0.3
x × 58.5 + y × 74.5 = 20.75
17.55 - 58.5 y + 74.5 y = 20.75
3.2 = 16y
y = 0.2 moli KCl
masa KCl = 14.9 g
masa NaCl = 20.75 - 14.9 = 5.85 g