Question

amplifica fractia algebrica 2x+1 supra x+2 cu (2-x)
va rog dau 50 p

Answer 1

[(2x+1)/(x+2)] * (2-x) = (2x+1)(2-x)/(x+2)(2-x) = (4x-2x^2+2-x)/-(x+2)(x-2) = (-2x^2+3x+2)/-(x^2-4) = -(2x^2-3x-2)/-(x^2-4) = (2x^2-3x-2)/(x^2-4)

Answer 2

2x+1/x+2     amplificată cu  (2-x)

(2x+1)(2-x) / (x+2)(2-x)=

2x(2-x) +1(2-x) / x(2-x) +2(2-x)=

4x - 2x² + 2 - x / 2x - x² +4 - 2x =

- 2x² +3x +2 / - x² +4

Sper că te-am ajutat!