Question

Amplificati raportul algebric √3x-4/√3x+4 cu 4-√3x​

Answer 1

Răspuns:

(x√3-4)/(x√3+4)  ×( 4-x√3)/(4-x√3) =

=(x√3-4)( 4-x√3)/(x√3+4)( 4-x√3) =

=-(x√3-4)(x√3-4)/(4+x√3)( 4-x√3) =

=-(3x²-8x√3+16)/(16-3x²)=

=(3x²-8x√3+16)/(3x²-16)