Question

Analizati seria omoloaga a acizilor carboxilici si realizati in acelasi mod si pentru n=5 si n=6(sa contina si toate structurile, formula, denumirea, exact asa cum este si la celelalte)​

Answer 1

n=5

CH3-CH2-CH2-CH2-COOH acid pentanoic

CH3-CH(CH3)-CH2-COOH acid 2 metil butanoic

CH3-CH2-CH(CH3)-COOH acid 3 metil butanoic

CH3-C(CH3)2-COOH acid 2,2 dimetil propanoic

CH3-CH(CH2-CH3)-COOH acid 2 etil propanoic

n=6

CH3-CH2-CH2-CH2-CH2-COOH acid hexanoic

CH3-CH(CH3)-CH2-CH2-COOH acid 2 metil pentanoic

CH3-CH2-CH(CH3)-CH2-COOH acid 3 metil pentanoic

CH3-CH2-CH2-CH(CH3)-COOH acid 4 metil pentanoic

CH3-C(CH3)2-CH2-COOH acid 2, 2 dimetil butanoic

CH3-CH(CH3)-CH(CH3)-COOH acid 2, 3 dimetil butanoic

CH3-CH2-C(CH3)2-COOH acid 3, 3 dimetil butanoic

CH3-CH(CH2-CH3)-CH2-COOH acid 2 etil butanoic

CH3-CH2-CH(CH2-CH3)-COOH acid 3 etil butanoic

CH3-CH(CH2-CH3-CH3)-COOH acid 2 propil propanoic

CH3-CH(CH3-CH2-CH3)-COOH acid 2 izopropil propanoic

CH3-CH(CH3)-CH(CH2-CH3)-COOH acid 3 etil 2 metil propanoic

CH3-C(CH3)(CH2-CH3)-CH2-COOH acid 2 etil 2 metil propanoic

CH3-CH2-C(CH3)(CH2-CH3)-COOH acid 3 etil 3 metil propanoic

*na: daca vezi (CH3) in paranteza, inseamna ca se leaga de carbonul respec si tb sa l pui sub si/sau deasupra

sper ca te am ajutat!