Question

Arata ca 2 la puterea 103+7la puterea81 se divide prin 5

Answer 1

$2 {}^{110} {7}^{81}$

trebuie scris ca ceva la puterea a 5 (respectiv un multiplu a numarului 5
=>
${2}^{110} + (5 + {2)}^{81}$
${2}^{110} + {5}^{81} + {2}^{81}$

${2}^{110 + {81}^{} } + {5}^{81}$
${2}^{191} + {(2 + 3)}^{81}$
2
${2}^{191} + {2}^{81} + {3}^{81}$
${2}^{272} + {(2 + 1)}^{81}$
${2}^{272} + {2}^{81} + {1}^{81}$
${2}^{353} + 1$
$( {2}^{70.6 )\times } {}^{5}$