Question

Arata ca:2^n×3^n×5^n+2^n×15^n×14+3^n×10^n×2 divizibil cu 17;

Answer 1

2^n×3^n×5^n+2^n×15^n×14+3^n×10^n×2=
=2^n×3^n×5^n+2^n×3^n×5^n×14+3^n×2^n×5^n×2=
=2^n×3^n×5^n×(1+14+2)=
=2^n×3^n×5^n× 17 deci  divizibil cu 17