Question

Arata ca (4^n×6^n+1+8^n×3^n+1-2^3n+1×3^n)divizibil la 56

Answer 1

4^n × 6^(n+1) + 8^n×3^(n+1) - 2^3(n+1) ×3^n

=2^2n x 2^nx3^nx6 + 2^3nx3^nx3 - 2^3nx2x3^n

=2^3n x 3^n (6+3-2)

=8^nx3^nx7

=7x8x8^(n-1) x3^n

=56x3^n x 8^(n-1), e divizibil cu 56   (pt n diferit de 0)

Answer 2

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