Question

Arata ca:5|(3²+4²) si 10|(17²+1)
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Answer 1

$5 |( {3}^{2} + {4}^{2} )$

$5 |(9 + 16)$

$5 |25 \: \: (A)$

$25 \div 5 = 5 \: \in \: \mathbb{Z}$

$10 |( {17}^{2} + 1)$

$10 |(289 + 1)$

$10 |290 \: \: (A)$

$290 \div 10 = 29 \: \in \: \mathbb{Z}$