Question

arata ca urmatoarele nr sunt patrate perecte si cuburi perfecte 7la putetea18 8la puterea 8 ,27la puterea10, 25 la puterea 15, 4la puterea 9,si 2la puterea 10× 4la puterea 10.​

Answer 1

$7^{18}=7^{6*3}=(7^6)^3\\8^8=(2^3)^8=2^{3*8}=(2^8)^3\\27^{10}=(3^3)^{10}=3^{3*10}=(3^{10})^{3}\\25^{15}=25^{5*3}=(25^5)^{3}\\4^9=4^{3*3}=(4^3)^3\\2^{10}*4^{10}=(2*4)^{10}=8^{10}=(2^{10})^3$

Answer 2

Răspuns:

Explicație pas cu pas:

7^18 = (7^9)^2 patrat perfect

7^18 = (7^6)^3 cub perfect

8^8 = (8^4)^2 patrat perfect

8^8 = (2^3)^8 = (2^8)^3 cub perfect

27^10 = (27^5)^2 patrat perfect

27^10 = (3^3)^10 = (3^10)^3 cub perfect

25^15 = (5^2)^15 = (5^15)^2 patrat perfect

25^15 = (25^3)^5 = (25^5)^3 cub perfect

4^9 = (2^2)^9 = (2^9)^2 patrat perfect

4^9 = (4^3)^3 cub perfect

2^10 * 4^10 = 8^10 = (8^5)^2 patrat perfect

2^10 * 4^10 = 8^10 = (2^3)^10 = (2^10)^3 cub perfect