Question

Aratati: 3(2+radical2)-radical18=6

Answer 1

3(2+√2)-√18=6+3√2-3√2=6

Answer 2

       
$3(2+ \sqrt{2})- \sqrt{18} = \\ =3*2+ 3*\sqrt{2})- \sqrt{9*2}= \\ =6+3 \sqrt{2} -3 \sqrt{2}=6 \\ cctd$