Question

Aratati ca √16-√32+√18+√2-2^2=0

Answer 1

$\sqrt{32} = \sqrt{16 \times 2} \\ \sqrt{18} = \sqrt{9 \times 2} \\ 4 - 4 \sqrt{2} + 3 \sqrt{2} + \sqrt{2} - 4 = 4 - 4 - 4 \sqrt{2} + 4 \sqrt{2} = 0$