Question

aratati ca 2^6n divide (8^(2n+1)+4^(3n+1)-11*64^n)

Answer 1

$8^{2n+1}+4^{3n+1}-11*64^n=$
$=(2^3)^{2n}*8+(2^2)^{3n}*4-11*(2^6)^n=$
$=2^{6n}*8+2^{6n}*4-11*2^{6n}=$
$=2^{6n}(8+4-11)=$
$=2^{6n}$