Question

Aratati ca(2^n+2+2^n)divizibil(4^n+1+4^n),pt orice neN

Answer 1

(2^n+2+2^n) =2^n(2²+2⁰)=2^n × (4+1)= 2^n  × 5

(4^n+1+4^n)=2^2n+2+2^2n=2^2n(2²+2⁰)=2^2n ×(4+1)=2^2n × 5  divizibil cu 2^n × 5