Question

aratati ca (2^n+2n) I (4^n+1+4^n), pentru orice numar natural n

Answer 1

(2^n+2+2^n)/(4^n+1+4^n)=

=(2^n+2+2^n)/(2^2n+2+2^2n)=

=2^n(4+1)/[2^2n(4+1)]=

=2^n × 5/2^2n ×5=

=2^n/2^2n=

=2/2²=

=1/2

Sper ca e corect:) si ca te-am ajutat