Question

Aratati ca
√3+√12-3√3=0

Answer 1

$\sqrt{3}$+$\sqrt{12}$-3$\sqrt{3}$=$\sqrt{3} +2 \sqrt{3} -3 \sqrt{3} =2-3 \sqrt{3}-3 \sqrt{3}=0$

Answer 2

√3+√12-3√3=0
√3+√4*3-3√3=0
√3+2√3-3√3=0
3√3-3√3=0