Question

Aratati ca:
a) [(2^8)^3:8:(2^6+2^6)-16^3x4^5:2^8]:2^12+2=2
b)2^10+2^56:(2x2^2x2^20)^2=11
c)(2^32-4^16):(2^37+5^10)=0

Answer 1

a) [(2^8)^3:8:(2^6+2^6)-16^3x4^5:2^8]:2^12+2=
=[(2^24:2^3:(2^6)(1+1)-2^12x2^10:2^8]:2^12+2=
=(2^24:2^3:2^7-2^22:2^8):2^12+2=
=(2^14-2^14):2^12+2=
=0:2^12+2=
=0+2=2

b)2^10+2^56:(2x2^2x2^20)^2=
=2^10+2^56:(2^23)^2=
=2^10+2^56:2^46=
=2^10+2^10=
=2^10(1+1)=
=2^10×2=
=2^11

c)(2^32-4^16):(2^37+5^10)=
=(2^32-2^32):(2^37+5^10)=
=0:(2^37+5^10)= 0