Question

Aratati ca \frac{2}{ \sqrt{3}-1 } - \sqrt{3} =1[/tex]

Answer 1

[tex]^{ \sqrt{3}+1 /}\frac{2}{ \sqrt{3}-1 } -^{ ( \sqrt{3}-1 )(\sqrt{3}+1)/} \sqrt{3} =1 \\ \\ \frac{2 \sqrt{3}+2 }{ (\sqrt{3}-1)( \sqrt{3}+1)}- \frac{ \sqrt{3} (\sqrt{3+1})( \sqrt{3}-1 ) }{(\sqrt{3}-1)( \sqrt{3}+1)}=1 \\ \\ \frac{2 \sqrt{3}+2 }{3-1}- \frac{ \sqrt{3}(3-1) }{3-1}=1 \\ \\ \frac{2 \sqrt{3}+2- 2\sqrt{3}}{2}=1 \\ \\ \frac{2}{2}=1 \Longrightarrow \underline{\mathrm{ADEVARAT}} [/tex]