Question

aratati ca nr 49 se poate scrie ca suma de 12 patrate ale unor numere naturale

Answer 1

49 = 1*16+2*9+2*4+7*1

49 = 1*4^2 + 2*3^2 + 2*2^2 + 7*1^2 => suma de 12 patrate perfecte.

49 = 4^2 + 3^2 +3^2 + 2^2 +2^2 +1^2 + 1^2+ 1^2+ 1^2+ 1^2+ 1^2+ 1^2.

Xenon54

Answer 2

1 = 1² = pătrat perfect

4 = 2² = pătrat perfect

9 = 3² = pătrat perfect

16 = 4² = pătrat perfect

25 = 5² = pătrat perfect

36 = 6² = pătrat perfect

$\bf 49 = 16 + 9 + 9 +4 + 4 + 1 + 1 + 1 + 1 + 1 + 1 + 1$

$\red{\bf 49={4}^{2}+{3}^{2}+{3}^{2}+{2}^{2}+{2}^{2}+{1}^{2}+{1}^{2}+{1}^{2}+{1}^{2}+{1}^{2}+ {1}^{2}+{1}^{2}}$