Question

aratati ca nr p=(1supra √2 +1 ) +(1 supra radical din 2 -1) totulla patrat

Answer 1

$\frac{1}{ \sqrt{2}+1 }$ totul la patrat + [tex] \frac{1}{ \sqrt{2}-1 } [/tex] totul la patrat
$\frac{1^{2} }{2+4+1} + \frac{ 1^{2} }{2-4+1} = \frac{1}{7} - \frac{1}{1} = \frac{1}{7} - \frac{7}{7} = \frac{7-7}{7} = \frac{0}{7} =0$
p=0