Question

aratati ca nr urmatoarele sunt naturale : a ) 3a+2b/a+b+c + 3b+2c / a+b+c + 3c+2a / a+b+c . VA ROG DIN SUFLET ❤

Answer 1

$a) \frac{3a + 2b}{a + b + c} + \frac{3b + 2c}{a + b + c} + \frac{3c + 2a}{a + b + c}$

$= \frac{3a + 3b + 3c + 2a + 2b + 2c}{a + b + c}$

$= \frac{3(a + b + c) + 2(a + b + c)}{a + b + c}$

$= \frac{(a + b + c)(3 + 2)}{a + b + c}$

$= \frac{3 + 2}{1}$

$= \frac{5}{1}$

$= 5$