Question

Arătați ca numerele:
a) n=4^41 × 9^47

Answer 1

n = patrat perfect 
4 ⁴¹ = (2 ² )⁴¹ = (2⁴¹ )² 
9⁴⁷ =(3² )⁴⁷ =(3⁴⁷ )²
n = (2⁴¹ ) ² · ( 3⁴⁷ )² = [ 2⁴¹· 3⁴⁷ ]²

Answer 2

$a)n= 4^{41}* 9^{47}=( 2^{2})^{41}*( 3^{2})^{47}=( 2^{41})^{2}*( 3^{47})^{2}=( 2^{41}* 3^{47})^{2}$ - pătrat perfect.