Question

Aratati ca numerele m+n este divizibil cu 12, unde m=2+4+6+...+100, iar n=11×(2+4+6+...+100).

Answer 1

[tex]m=2+4+6+...+100\\ m=2(1+2+3+...+50)\\ m=\not2*\frac{50*51}{\not2}\\ m=50*51\\ n=11*2(1+2+3+...+50)\\ n=11*\not2*\frac{50*51}{\not2}\\ n=11*50*51\\ m+n=50*51+11*50*51\\ m+n=50*51(1+11)=50*51*12[/tex]