Aratati ca numerele x si y sunt patrate peefecte:
X=[2^30^2×(2^6)^100 ×2+(64^4)^100÷2^899]^2]+2^3007
Y=5×(3^2002-3^2001-9^1000)
blindseeker90:
La prima ecuatie ai niste paranteze patrate care sunt in plus. Ai scris bine ecuatia?
Da,este scrisă corect
Răspunsuri la întrebare
Răspuns de
10
X=[(2³⁰)²×(2⁶)¹⁰⁰ ×2+(64⁴)¹⁰⁰:2⁸⁹⁹]²+2³⁰⁰⁷=
x=[2⁶⁰x2⁶⁰⁰x2+64⁴⁰⁰:(2⁸⁹⁹)²]+2³⁰⁰⁷
x=[2⁶⁰⁺⁶⁰⁰⁺¹+(2⁶)⁴⁰⁰:2¹⁷⁹⁸]+2³⁰⁰⁷
x=[2⁶⁶¹+2²⁴⁰⁰:2¹⁷⁹⁸]+2³⁰⁰⁷
x=[2⁶⁶¹+2²⁴⁰⁰⁻¹⁷⁹⁸]+2³⁰⁰⁷
x=[2⁶⁶¹+2⁶⁶²]+2³⁰⁰⁷
x=2⁶⁶¹(1+2)+2³⁰⁰⁷
x=3x2⁶⁶¹+2³⁰⁰⁷
Y=5×(3²⁰⁰²-3²⁰⁰¹-9¹⁰⁰⁰)
Y=5x(3²⁰⁰²-3²⁰⁰¹-(3²)¹⁰⁰⁰)
Y=5x(3²⁰⁰²-3²⁰⁰¹-3²⁰⁰⁰)
Y=5x3²⁰⁰⁰(3²-3-1)
Y=5x3²⁰⁰⁰x5
y=25x2²⁰⁰⁰
x=[2⁶⁰x2⁶⁰⁰x2+64⁴⁰⁰:(2⁸⁹⁹)²]+2³⁰⁰⁷
x=[2⁶⁰⁺⁶⁰⁰⁺¹+(2⁶)⁴⁰⁰:2¹⁷⁹⁸]+2³⁰⁰⁷
x=[2⁶⁶¹+2²⁴⁰⁰:2¹⁷⁹⁸]+2³⁰⁰⁷
x=[2⁶⁶¹+2²⁴⁰⁰⁻¹⁷⁹⁸]+2³⁰⁰⁷
x=[2⁶⁶¹+2⁶⁶²]+2³⁰⁰⁷
x=2⁶⁶¹(1+2)+2³⁰⁰⁷
x=3x2⁶⁶¹+2³⁰⁰⁷
Y=5×(3²⁰⁰²-3²⁰⁰¹-9¹⁰⁰⁰)
Y=5x(3²⁰⁰²-3²⁰⁰¹-(3²)¹⁰⁰⁰)
Y=5x(3²⁰⁰²-3²⁰⁰¹-3²⁰⁰⁰)
Y=5x3²⁰⁰⁰(3²-3-1)
Y=5x3²⁰⁰⁰x5
y=25x2²⁰⁰⁰
Alte întrebări interesante