Question

Aratati ca x si y sunt patrate perfecte
x=[2^30^2×(2^6)^100×2+(64^4)^100:2^899]^2+2^3007
y=5×(3^2002-3^2001-9^1000)
Este urgent va rog frumos!!!
PS.^inseamna la puterea

Answer 1

x=[2^30^2×(2^6)^100×2+(64^4)^100:2^899]^2+2^3007

x=[2^900×2^600×2+(2^6^4)^100:2^899]^2+2^3007

x=[2^1500×2+(2^24)^100:2^899]^2+2^3007

x=[2^1501+2^2400:2^899]^2+2^3007

x=[2^1501+2^1501]^2+2^3007

x=[2^1502]^2+2^3007

x=2^3004+2^3007

x=2^3004(1+2^3)

x=2^3002*9

x=(2^1501)^2*3^2
deci sunt patrate perfecte




y=5×(3^2002-3^2001-9^1000)

y=5×(3^2002-3^2001-3^2000)

y=5×3^2000(3^2-3-1)

y=5×3^2000x5

y=5^2×(3^1000)^2 deci este patrat perfect