Question

Aratati:
$\sqrt{6} ( \sqrt{3} - \sqrt{2} ) - 3 \sqrt{2} + 2 \sqrt{3} + 1 = 1$
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Answer 1

$\sqrt{6} \times \sqrt{3} - \sqrt{6} \times \sqrt{2 } - 3 \sqrt{2} + 2 \sqrt{3} + 1 = 1 \\ 3 \sqrt{2} - 2 \sqrt{3} - 3 \sqrt{2} + 2 \sqrt{3 } + 1 = 1 \\ 1 = 1$