Question

Are cineva rezolvat exercitiul 12 de la examenul de matematica de anul trecut ?

Answer 1

$a+ a^{2} -2=0=\ \textgreater \ a^{2}+a-2=0=\ \textgreater \ (a-1)(a+2)=0=\ \textgreater \ \\ \left \{ {{a=1} \atop {a=-2}} \right. a=1 ;a=-2$