Question

aria paralelogramului ABCD ,cu AD perpendicular pe BD, AB=10cm,AD=6cm,BD=8cm este egala cu..

Answer 1

$\bf AD \perp BD \implies \angle ADB =90^{\circ}$

$\bf In \;\; \triangle ABD \; \; avem:$

$\bf AD = 6\, cm \; (cateta)$

$\bf AB = 10\, cm \; (ipotenuza)$

$\bf BD = 8 \, cm \; (cateta)$

$\bf \implies h= \dfrac{c_1 \cdot c_2}{ip} =\dfrac{6 \cdot 8 }{10 } = 4,8 \, cm$

$\bf A_{ABCD} = b \cdot h = 10 \, cm \cdot 4,8 \, cm$

$\bf \implies \boxed{\bf A_{ABCD}=48\, cm^2}$

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