Question

Aso Rizales S = 1+ 2+ 3+..... +50 S = 7+8+ 9+...... +68 S=6+7+8.......+34​

Answer 1

Răspuns:

Explicație pas cu pas:

Teorema Gauss

a)S=1+2+3+...+50=[(1+50)×50]÷2=1275

b) S=1+2+3+4+5+6+7+8+...+68-S1=[(1+68)×68]÷2-21= 2325

UndeS1=1+2+3+...+6=[(1+6)×6]÷2=21

c) S= 1+2+3+4+5+6+7+..+34-S2= [1+34)×34]÷2-15=580

UndeS2=1+2+..5=(1+5)×5÷2=15