Question

Asta de jos ... si x patrar + 4 = x+4
Stiam ca se face cu delta .. o rezolvati va rog urgent daca se poate

Answer 1

2x+4 = x²+3x+2
2x+4-x²-3x-2 = 0
-x²-x+2 = 0

∆ = b²-4ac
∆ = 1-4•(-1)•2
∆ = 1+8
∆ = 9.

x1 = (-b+√∆)/2a
x1 = (1+3)/-2
x1 = 4/-2 --> x1 = -2.

x2 = (-b-√∆)/2a
x2 = (1-3)/-2
x2 = -2/-2
x2 = 1.

a(x-x1)(x-x2) = -(x+2)(x-1).



x²+4 = x+4
x²+4-x-4 = 0
x²-x = 0
x(x-1) = 0

x1 = 0
x2 = 1.




J'espère aidé :)