Question

Astazi am dat un test la mate si am rezolvat iar subiectul acasa. Nu sunt sigur ca este corect. Ma puteti ajuta va rog?

[0,1(6) - 0,(4) + 0,08(3)] : 2 intregi si 1/3 + 5/6.

Mentionez ca sunt clasa a 7-a. Mie rezultatul mi-a dat 275/300. Multumesc anticipat!

Answer 1

$[0,1(6) - 0,(4) + 0,08(3)] : 2 \frac{1}{3}+ \frac{5}{6}\\ \\ 0,1(6)=\frac{16-1}{90}=\frac{15}{90}= \frac{1}{6} ; 0,(4)=\frac{4}{9} ;0,08(3)=\frac{83-8}{900}=\frac{75}{900}=\frac{1}{12};2\frac{2}{3}= \frac{2\cdot3+1}{3}=\frac{7}{3}$

$(\frac{1}{6}-\frac{4}{9}+\frac{1}{12}): \frac{7}{3}+\frac{5}{6}=$

$(\frac{^{2)}1 }{6}-\frac{^{4)}4}{9}+\frac{^{3)}1}{12}): \frac{7}{3}+\frac{5}{6}=(\frac{2}{36}-\frac{16}{36}+\frac{3}{36}): \frac{7}{3}+\frac{5}{6}=(\frac{2-16+3}{36}): \frac{7}{3}+\frac{5}{6}=-\frac{11}{36}: \frac{7}{3}+\frac{5}{6}=-\frac{11}{36}\cdot\frac{3}{7}+\frac{5}{6}=-\frac{11}{2\cdot7}+ \frac{5}{6}=\frac{-33+42}{42}=\frac{9}{42}$