Question

Avand la dispozitie HCL 37% (ρ=1,19 g/$cm^{3}$) sa se prepare 500 ml solutie HCL 2N (mase atomice: H-1 Cl-35,4)

Answer 1

ro=ms/V=>ms=1,19*500=595g HCl

C=md/ms*100=>md=37*595/100=220,15g HCl

ms=md+mH2O=>mH2O=ms-md=595-220,15=274,85g H2O

Se cantaresc 220,15g HCl si se dizolva in 274,85mL H2O

nu sunt sigur..