Question

avend 600 g solutie de concentratie 32 % ce masura ar trebui inlocuita cu apa pentru a ramane aceeasi cantitate de solutie 24%.

Answer 1

c1=md/ms1*100 ⇒ md=32*600/100 ⇒ md=192g
ms1=md+mH2O=600
c2=md/ms2*100 ⇒ ms2=192/24*100 ⇒ ms2=800
ms2=md+mH2O+mH2O aditionala⇒ 800=600+mH2O aditionala
mH2O aditionala=200 g