Question

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Answer 1

 

$\displaystyle\bf\begin{cases}x+3y=2~~~|~\times3\\-3x-y=2\end{cases}\\\\\\\begin{cases}3x+9y=6\\-3x-y=2\end{cases}\\\\~~~~~/~~~~~8y=8\\\\y=\frac{8}{8}\\\\\boxed{\bf y=1}\\\\x+3y=2\\x=2-3y\\x=2-3\times1\\\\x=2-3\\\boxed{\bf x=-1}$