Question

b) [1,(3) +0,5]: 2,2;

e) [1,75 - 0,(5)]: 21,5;


c) (3,5+0,(6)] . 0,6;

f) [2,75 - 2,(6)] · 14,

d) [1,25 +0,(6)]: 11,5; 14.

Calculaţi: c) [0,8(3). 0,75 -0,(3)]: 3,5;

va rog dau coroana​

Answer 1

Răspuns:

Explicație pas cu pas:

B) [1,(3) +0,5]: 2,2=[(13-1)/9+5/10]:22/10=(12/9+1/2]:11/5=(4/3+1/2):11/5= [(8+3)/6]·5/11=(11/6)·(5/11)=(11·5)/(6·11)=5/6

e) [1,75 - 0,(5)]: 21,5=(175/100-5/9):215/10=(7/4-5/9):43/2= [(63-20)/36]:43/2 = (43/36)·(2/43)=(43·2)/(36·43)=2/36=1/18

c) (3,5+0,(6)] . 0,6= (35/10+6/9)·6/10= (7/2+2/3)·6/10=(21+4)/6·(6/10)= (25/6)·(6/10)=(25·6)/(6·10)=25/10=5/2

f) [2,75 - 2,(6)] · 14= [275/100-(26-2)/9]·14=(11/4-24/9)·14=(11/4-8/3)·14=[(33-32)/12]·14= (1/12)·14=14/12=7/6

d) [1,25 +0,(6)]: 11,5; 14.  Aici apare un 14, dupa punct si virgula, exercitiul nu e clar, imi pare rau dar nu pot sa-l fac.

Calculaţi: c) [0,8(3). 0,75 -0,(3)]: 3,5= [(83-8)/90·75/100-3/9]:35/10= (75/90)·75/100-1/3]:35/10= [(25/30)·(3/4)-1/3]·10/35=

[(25·3)/(30·4)-1/3]·10/35=[25/(10·4)-1/3]·10/35=(5/8-1/3)·2/7= [(15-8)/24]·2/7= (7/24)·(2/7)= (7·2)/(24·7)=2/24=1/12