Question

b) [1,(3) +0,5]: 2,2;

e) [1,75 - 0,(5)]: 21,5;

c) (3,5+0,(6)] . 0,6;

f) [2,75 - 2,(6)] · 14,

d) [1,25 +0,(6)]: 11,5; 14.

Calculaţi: c) [0,8(3). 0,75 -0,(3)]: 3,5;

va rog dau coroana​​

Answer 1

Explicație pas cu pas:

b) [1,(3) +0,5]: 2,2

$( \frac{13 - 1}{9} + \frac{1}{2}) \div \frac{22}{10} = ( \frac{12}{9} + \frac{1}{2}) \times \frac{10}{22} =( \frac{4}{3} + \frac{1}{2}) \times \frac{5}{11} = \frac{8 + 3}{6} \times \frac{5}{11}= \frac{11}{6} \times \frac{5}{11} = \frac{5}{6}=0,8(3)$

c) (3,5+0,(6)] . 0,6

$( \frac{35}{10} + \frac{6}{9} ) \times \frac{6}{10} = ( \frac{7}{2} + \frac{2}{3}) \times \frac{3}{5} = \frac{21 + 4}{6} \times \frac{3}{5} = \frac{25 \times 3}{6 \times 5} = \frac{5}{2}=2,5$

d) [1,25 +0,(6)]: 11,5

$( \frac{125}{100} + \frac{6}{9} ) \div \frac{115}{10} = ( \frac{5}{4} + \frac{2}{3}) \times \frac{10}{115} = \frac{15 + 8}{12} \times \frac{2}{23} = \frac{23 \times 2}{12 \times 23} = \frac{1}{6}=0,1(6)$

e) [1,75 - 0,(5)]: 21,5

$( \frac{175}{100}-\frac{5}{9} ) \div \frac{215}{10}= (\frac{7}{4} - \frac{5}{9} ) \times \frac{10}{215} = \frac{63 - 20}{36} \times \frac{2}{43} = \frac{43 \times 2}{36 \times 43} = \frac{1}{18}=0,0(5)$

f) [2,75 - 2,(6)] · 14

$( \frac{275}{100} - \frac{26 - 2}{9} ] \times 14 = ( \frac{11}{4} - \frac{24}{9} ) \times 14 = ( \frac{11}{4} - \frac{8}{3}) \times 14 = \frac{33 - 32}{12} \times 14 = \frac{14}{12} = \frac{7}{6}=1,1(6)$

c) [0,8(3). 0,75 -0,(3)]: 3,5

$( \frac{83 - 8}{90} \times \frac{75}{100} - \frac{3}{9}) \div \frac{35}{10} \\ = ( \frac{75}{90} \times \frac{3}{4} - \frac{1}{3} ) \times \frac{10}{35} \\ = ( \frac{5}{6} \times \frac{3}{4} - \frac{1}{3} ) \times \frac{2}{7} \\ = (\frac{5}{8} - \frac{1}{3} ) \times \frac{2}{7} \\ = \frac{15 - 8}{24} \times \frac{2}{7} \\ = \frac{7 \times 2}{24 \times 7} \\ = \frac{1}{12}= 0,08(3)$