Question

b)1+3+...+(2x-1)= 100.

Answer 1

Explicație pas cu pas:

$\boxed{ 1 + 3+ 5 + ... + (2n - 1) = {n}^{2}}$

=>

$1+3+...+(2x-1) = 100$

${x}^{2} = 100 \iff {x}^{2} = {10}^{2}$

$x \in \mathbb{N} \implies x = 10$