Question

(b-1)(b+1)(b la a 2-a +1)(b la a 4-a +1) +1
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Answer 1

$(b-1)(b+1) b^{2}+1$)($b^{4}+1$)+1$=(b^{2}-1)(b^{2}+1)(b^{4}+1)+1= \\ =(b^{4}-1)(b^{4}+1)+1= \\ =b^{8}-1+1= \\ =b^{8}.$=