Question

b)10,1:[(6/5+13/6)×(21/10+6/13)]:1,(4)Va rog

Answer 1

b)101/10:[(6/5+13/6)×(21/10+6/13)]:13/9
aducând la același numitor în parantezele rotunde ,pt prima 30,pt a doua 130
101/10:[(36+65)/30×(273+60)/130]×9/13=
101/10:(101/30×333/130)×9/13=
101/10:(101×111/10×130)×9/13=
101/10×(10×130)/101×111×9/13=
130/111×9/13=90/111