Question

[(B-16)×12-80]÷8÷10=5
2•{2+2•[2+2•(6-2•×)}[=28

Answer 1

Răspuns

Explicație pas cu pas:

[(b-16)*12-80]:8:10=5

[(b-16)*12-80]:8=10*5

[(b-16)*12-80]:8=50

[(b-16)*12-80]=50*8

[(b-16)*12-80]=400

(b-16)*12=400+80

(b-16)*12=480

b-16=480:12

b-16=40

b=40+16

b=56

2*{2+2*[2+2*2(6-2x)]}=28

2+2*[2+2*(6-2x)]=28:2

2+2*[2+2*(6-2x)]=14

2*[2+2*(6-2x)=14-2

2*[2+2*(6-2x)=12

2+2*(6-2x)=6

2*(6-2x)=6-2

2*(6-2x)=4

6-2x=4:2

6-2x=2

6-2=2x

2x=4

x=4:2

x=2