Question

b) (3^2•2^6-2^5•6):12 -2^5
c) (7^4 - 7^3):(7^2 – 7)-2^3•5
Dau coroana!

Answer 1

b) (3² • 2^6 - 2^5 • 6) : 12 - 2^5 (9 • 64 - 32 • 6) : 12 - 32 = (576 - 192) : 12 - 32 = 384 : 12 - 32 = 32 - 32 = 0

c) (7^4 - 7^3) : (7^2 - 7) - 2^3 • 5 = (2 401 - 343) : (49 - 7) -8•5 = 2058 : 42 -40 = 49 - 40 = 9

Answer 2

$\it b)\ (3^2\cdot2^6-2^5\cdot6):12-2^5 =2^5(9\cdot2-6):12-2^5=2^5\cdot12:12-2^5=\\ \\= 2^5-2^5=0$

$\it c)\ (7^4-7^3):(7^2-7)-2^3\cdot5=7^2(7^2-7):(7^2-7)-8\cdot5=49-40=7$